00:01
In our question, we are given three resistors, r1, r2 and r3 which are connected to a source of terminal voltage v of magnitude 6 volts.
00:11
We need to find the current that would pass through each resistor and the voltage across if they are connected a in series and secondly in parallel circuit.
00:25
Consider the first case of series circuit.
00:27
Now we are given the values of each resistor to be r1, 2 oom, r2 of 4 oom, and r3 resistor of 8 oom.
00:39
The terminal voltage of magnitude 6 volts.
00:42
Now in series, the current passing through the circuit will be given as terminal voltage divided by the equivalent resistance of the circuit.
00:51
Now given the equivalent resistance having in series circuit will be given as the sum of the resistors r1, r2 and r3 by v.
01:03
Substitute in the values, 6 volts divided by 2 plus 4 plus 8m, which gives us the current to be equal to 0 .4286 ampere...