00:01
In the question we are given an lti system for which we are given that d square yt divided by dt square plus 3dyt divided by dt plus 2yt is equals to 2dxt divided by dt plus 6xt.
00:27
T.
00:28
This is the given equation or the differential linear constant coefficient differential equation.
00:42
Difference equation.
00:44
We can say both the names.
00:46
We are given that let x t is equals to 2 e raised to the power minus t u t.
00:54
Now these are the given conditions to us in the question.
00:58
According to to this we need to find the output that is output yt, yt.
01:07
Now we know that output yt is equals to inverse laplace transform, laplace transform of ys.
01:19
Therefore we need to first find the laplace transform of ys.
01:24
Now to find this we know s raised to the power of ys plus 3s ys plus 2 ys is equals to 2s into s plus 6 into s.
01:39
This is the laplace transform for the first equation that we were given.
01:43
So ys taking as common s raised to the power 3 plus 3s plus 2 is equals to 2s plus 6 into s.
01:52
That is we can write it as hs is equal to ys divided by xs.
01:58
Now put the value of ys...