The position of an object is given by x = at3 - bt2 + ct, where a = 4.1 m/s3, b = 2.2 m/s2, c =

Name: The position of an object is given by x = at3 - bt2 + ct, where a = 4.1 m/s3, b = 2.2 m/s2, c = 1.7 m/s, and x and t are in SI units. What is the instantaneous acceleration of the object when t = 0.7 s?
Uploaded: 2022-02-06T22:05:52-08:00
Duration: 2 min 1 s
Channel: Nishant Kumar
Description: The position of an object is given by x = at3 - bt2 + ct, where a = 4.1 m/s3, b = 2.2 m/s2, c = 1.7 m/s, and x and t are in SI units. What is the instantaneous acceleration of the object when t = 0.7 s?

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Nishant Kumar · Accepted Answer

Step 1: Given the position equation X = at^3 + bt^2 + ct, where a = 4 m/s^3, b = 2.2 m/s^2, c =

Question

The position of an object is given by x = at3 - bt2 + ct, where a = 4.1 m/s3, b = 2.2 m/s2, c = 1.7 m/s, and x and t are in SI units. What is the instantaneous acceleration of the object when t = 0.7 s?

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