00:01
In this question, we have been given the probability distribution of x, which represents a number of students typically absent from class on monday is as follows.
00:10
As you can see in the table here, okay, we need to sketch a probability function of x.
00:15
So let us draw the graph for the x.
00:18
So our graph will be somewhat of this same.
00:23
So let me draw the graph first.
00:25
So let's say this is x 0, 1, 2, 3, 4, 5, 6, and this is 7, okay? and this is my f of x, so i will plot 0 .1, and i will be having 0 .2 and then 0 .3.
00:50
So this side we are having f of x and this is x.
00:56
Okay so for 1 x0 we are having 0 .005 okay so it will be somewhere here correct now for 1 we are having 0 .25 so somewhere here then for 2 it is 0 .310 so 0 .310 will be somewhere here correct then for 3 it is 0 .340 so above that so this is what i will get then then for 4 .22.
01:31
So point 22 will be somewhere here.
01:35
Then for 5 it is 0 .080.
01:38
So it will be somewhere here.
01:40
Then for 6 .019.
01:43
So it is very close to this.
01:46
And 0 .701 nearly this.
01:48
Okay.
01:49
So just now, now we have to just join these points.
01:53
So this will be somewhat of this same.
01:56
Okay.
01:57
So this will be my graph of the function f of x.
02:04
So this is how we can draw the graph.
02:07
Now let us see the second part.
02:09
In the second part, we need to find the probability on monday, either two, three, or four student will be absent.
02:17
So probability will be equal to f of two plus f of three plus f of four, and all the values we know, it is 0 .310 .340 .220 and that is equal to 0 .870.
02:42
So this will be the required probability.
02:46
Now, for the c part, we need to find out the probability that on a given monday, more than three students are absent.
02:54
So in this case, the probability, more than these students are absent, means what? they can be 4, 5, 6 or 7...