00:01
We are asked to consider a 250 gram metal bar.
00:05
We are told that 5 ,866 joules of energy are introduced into the system, and the temperature raises from 22 degrees celsius to 100 degrees celsius.
00:19
Let's go ahead and figure our change of temperature will equal 100 .0 degrees celsius, 22 .0 degrees celsius.
00:28
That'll give me 78 .0 degrees celsius is my delta t.
00:33
We will be finding the specific heat using q equals mc delta t.
00:42
We'll be solving for a specific heat which will equal q over m times delta t.
00:49
Let's go ahead and substitute our values.
00:54
250 joules over, it wasn't 250 joules.
01:03
It was 5 ,866 joules over 250 grams and 7 ,866...