Question

30.0 mL of 0.400 M Zn$^{2+}$ is mixed with 100.0 mL of 0.200 M F$^-$ (Ksp ZnF$_2$ = 0.030). In the mixture you would observe A a precipitate forming. B no reaction taking place.

Name: 300 ml of 0400 m zn2 is mixed with 1000 ml of 0200 m f ksp znf2 0030 in the mixture you would observe a a precipitate forming b no reaction taking place 55306
Uploaded: 2022-04-18T10:43:12-08:00
Duration: 2 min 47 s
Channel: Suman K
Description: 300 ml of 0400 m zn2 is mixed with 1000 ml of 0200 m f ksp znf2 0030 in the mixture you would observe a a precipitate forming b no reaction taking place 55306

          30.0 mL of 0.400 M Zn$^{2+}$ is mixed with 100.0 mL of 0.200 M F$^-$ (Ksp ZnF$_2$ = 0.030).
In the mixture you would observe
A a precipitate forming.
B no reaction taking place.

300 ml of 0400 m zn2 is mixed with 1000 ml of 0200 m f ksp znf2 0030 in the mixture you would observe a a precipitate forming b no reaction taking place 55306

Added by Jessica S.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Suman K

04/18/2022

Step 1

Moles of Zn$^{2+}$ = 0.030 L $\times$ 0.400 mol/L = 0.012 mol Moles of F$^-$ = 0.100 L $\times$ 0.200 mol/L = 0.020 mol Show more…

Show all steps

Thanks for your feedback!

30.0 mL of 0.400 M Zn$^{2+}$ is mixed with 100.0 mL of 0.200 M F$^-$ (Ksp ZnF$_2$ = 0.030). In the mixture you would observe A a precipitate forming. B no reaction taking place.