Question

36. A driver accelerates when the car is going at a speed of 30 miles per hour (i.e., 44 feet per second). The velocity function is v(t) = 44 + 2.2t, where t is measured in seconds and the velocity is measured in feet per second. How far does the car travel between the time the driver hits the gas pedal and the time the car reaches the speed of 60 miles per hour (i.e., 88 feet per second)? Use a definite integral to find the answer. Compare your result to that of Exercise 24 in Section 4.1 and Exercise 74 in Section 4.2.

Uploaded: 2022-11-15T14:29:36-08:00
Duration: 3 min 40 s
Channel: Eduard Sanchez

          36. A driver accelerates when the car is going at a speed of 30 miles per hour (i.e., 44 feet per second). The velocity function is v(t) = 44 + 2.2t, where t is measured in seconds and the velocity is measured in feet per second. How far does the car travel between the time the driver hits the gas pedal and the time the car reaches the speed of 60 miles per hour (i.e., 88 feet per second)? Use a definite integral to find the answer. Compare your result to that of Exercise 24 in Section 4.1 and Exercise 74 in Section 4.2.

36. A driver accelerates when the car is going at a speed of 30 miles per hour (i.e., 44 feet per second). The velocity function is v(t) = 44 + 2.2t, where t is measured in seconds and the velocity is measured in feet per second. How far does the car travel between the time the driver hits the gas pedal and the time the car reaches the speed of 60 miles per hour (i.e., 88 feet per second)? Use a definite integral to find the answer. Compare your result to that of Exercise 24 in Section 4.1 and Exercise 74 in Section 4.2.

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Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Eduard Sanchez

11/15/2022

Step 1

e., 88 feet per second). We can do this by setting the velocity function equal to 88 and solving for t: 88 = 44 + 2.2t 44 = 2.2t t = 44 / 2.2 = 20 seconds So, the car reaches the speed of 60 miles per hour after 20 seconds. Show more…

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A driver accelerates when the car is going at a speed of 30 miles per hour (i.e., 44 feet per second). The velocity function is v(t) = 44 + 2.2t, where t is measured in seconds and the velocity is measured in feet per second. How far does the car travel between the time the driver hits the gas pedal and the time the car reaches the speed of 60 miles per hour (i.e., 88 feet per second)? Use a definite integral to find the answer. Compare your result to that of Exercise 24 in Section 4.1 and Exercise 74 in Section 4.2.