38. Suppose you have a random variable X with: X: 3, 6, 9, 12; $P(X = 3) = 0.2$, $P(X = 6) = 0.2$, $P(X = 9) = 0.3$, $P(X = 12) = 0.3$. (a) Compute E[X]. (b) Compute E[$X^2$]. (c) Hence, find Var(X).
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$E[X] = \sum_{i} x_i P(X = x_i) = 3(0.2) + 6(0.2) + 9(0.3) + 12(0.3) = 0.6 + 1.2 + 2.7 + 3.6 = 8.1$ Show more…
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