The equation s(t) = -16t^2 + 48t gives the height in feet of an object t seconds after it is thrown vertically at a speed of 48 ft/sec from ground level. The formula is valid until the object returns to ground level. How high above ground level will the object reach?
Added by James A.
Step 1
Given velocity function: v(t) = 32t + 48 Setting v(t) = 0, we get: 32t + 48 = 0 32t = -48 t = -48/32 t = 1.5 seconds Show more…
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