3(b) Find the vector form of the line with cartesian equation, 3x−1= y/4 =−(z−5).
Added by Dawn S.
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Given the Cartesian equation of the line: \[ 3x - 1 = \frac{y}{4} = -(z - 5) \] We can rewrite this equation in the form of a system of equations: \[ 3x - 1 = \frac{y}{4} \] \[ \frac{y}{4} = -(z - 5) \] From these equations, we can identify the direction ratios Show more…
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