Question

3. For the CE amplifier shown below, $R_{sig} = 10 \text{ k}\Omega$, $R_{B1} = 68 \text{ k}\Omega$, $R_{B2} = 27 \text{ k}\Omega$, $R_E = 2.2 \text{ k}\Omega$, $R_C = 4.7 \text{ k}\Omega$, and $R_L = 10 \text{ k}\Omega$. Assume $I_C = 0.8 \text{ mA}$, $\beta = 200$, unity gain $f_T = 1 \text{ GHz}$, and $C_\mu = 0.8 \text{ pF}$. (a) Neglecting $r_x$ and $r_o$, find the midband gain $A_M$ and the upper 3dB cutoff frequency $f_H$.

          3. For the CE amplifier shown below, $R_{sig} = 10 \text{ k}\Omega$, $R_{B1} = 68 \text{ k}\Omega$, $R_{B2} = 27 \text{ k}\Omega$, $R_E = 2.2 \text{ k}\Omega$,
$R_C = 4.7 \text{ k}\Omega$, and $R_L = 10 \text{ k}\Omega$. Assume $I_C = 0.8 \text{ mA}$, $\beta = 200$, unity gain $f_T = 1 \text{ GHz}$, and $C_\mu = 0.8 \text{ pF}$.
(a) Neglecting $r_x$ and $r_o$, find the midband gain $A_M$ and the upper 3dB cutoff frequency $f_H$.

3. For the CE amplifier shown below, Rsig = 10 kΩ, RB1 = 68 kΩ, RB2 = 27 kΩ, RE = 2.2 kΩ,
RC = 4.7 kΩ, and RL = 10 kΩ. Assume IC = 0.8 mA, β = 200, unity gain fT = 1 GHz, and Cμ = 0.8 pF.
(a) Neglecting rx and ro, find the midband gain AM and the upper 3dB cutoff frequency fH.

Added by Jose Antonio B.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Krishna J

Step 1

The midband gain is given by the formula: Am = -gm * (RC || RL) where gm is the transconductance of the transistor and RC || RL is the parallel combination of the collector resistor (RC) and the load resistor (RL). To find gm, we can use the formula: gm = Ic / Show more…

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For the CE amplifier shown below, Rsig = 10 kÎ©, RB1 = 68 kÎ©, RB2 = 27 kÎ©, RE = 2.2 kÎ©, Rc = 4.7 kÎ©, and R = 10 kÎ©. Assume Ic = 0.8 mA, Î² = 200, unity gain frequency (fr) = 1 GHz, and C = 0.8 pF. (a) Neglecting rx and ro, find the midband gain Am and the upper 3dB cutoff frequency f.