\(\int_0^{\pi} (\sin x) \sec^2 x \, dx\)
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The antiderivative of 3x^2 is (3/3)x^3 = x^3. The antiderivative of 2x is (2/2)x^2 = x^2. The antiderivative of 1 is x. So, the antiderivative of the function 3x^2 + 2x + 1 is x^3 + x^2 + x. Now, we can evaluate this antiderivative at the upper and lower limits Show more…
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