00:01
Hello student, here we are asked to reduce this circuit.
00:06
So, to reduce it we have to redraw it.
00:09
So, here we have a 15 volt voltage, 5 volt voltage, we have 4 ohm resistance here and then we have 4 ohm here and 8 ohm here, then we have 10 ohm.
00:50
Now, here 4 ohm, 2 4 ohm resistances are in parallel.
00:55
So, they combine as 2 ohm resistance, equivalent resistance of that is 2 ohm.
01:05
So, this 2 ohm, then if we further reduce it then this 10 ohm and 2 ohm are in series.
01:17
So, this will be equal to 12 ohm resistance.
01:23
So, this 4 ohm, this is 6, now we can draw it as, now here 4 ohm and 8 ohm are in series.
01:45
So, this is 12 ohm and this is also 12 ohm, this is 5 volt.
02:06
Now, if we further reduce it then this 12 ohm and 12 ohm are in parallel.
02:12
So, this will be 5 volt and here we have 4 ohm resistance and here this 12 ohm resistance, both 12 ohm resistance in parallel will be equivalent to a 6 ohm resistance.
02:43
Now, the current in this circuit i equals to 5 by 10 ampere.
02:52
So, this is 0 .5 ampere.
02:59
Now, so the current in this, so this resistance is 0 .5 ampere and so this current will now divide into two parts...