00:01
Hello students, let us consider the given values.
00:04
Voltage e1 24v, e2 12v, resistor value r1 28 ohm, r2 12 ohm, r3 16 ohm.
00:21
First we need to apply kvl that is kirchhoff's voltage law to the loop 1.
00:27
We get minus e1 plus i1 into r1 minus i2 into r2 plus e2 is equal to 0.
00:40
Let us consider this as equation 1.
00:44
Again apply kirchhoff's voltage law to loop 2.
00:48
We write minus e2 plus i2 into r2 plus i3 into r3 is equal to 0.
01:00
Consider this as equation 2.
01:04
Next we need to apply kirchhoff's current law at point a.
01:10
Then it will be i3 is equal to i1 plus i2 which is equation 3.
01:20
Now from equation 3 in equation 2 we can substitute i3 as i1 plus i2 so that we get minus e2 plus i2 r2 plus i1 into r3 plus i2 into r3 is equal to 0...