For the 2.0 $\Omega$ resistor, we have:
\[I_{2}=\frac{40 \mathrm{~V}}{2.0 \Omega}=20 \mathrm{~A}\]
For the 5.0 $\Omega$ resistor, we have:
\[I_{5}=\frac{40 \mathrm{~V}}{5.0 \Omega}=8.0 \mathrm{~A}\]
For the 8.0 $\Omega$ resistor, we have:
\[I_{8}=\frac{40
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