4. (10 pts) Determine the peak and average power delivered to a load resistor $R_L = 100 \Omega$ using a half-wave rectifier circuit driven by a 4:1 transformer tied to a 240 $V_{rms}$ ac source. Assume that the diode forward voltage $V_D = 0.7 V$.
Added by Alvin W.
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The peak voltage of the AC source can be calculated using the formula Vp = Vms * √2, where Vms is the RMS voltage. In this case, Vms = 240 V, so the peak voltage Vp = 240 * √2 = 339.4 V. Show more…
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