00:02
Solution of this question is, first we need to draw the diagram of this question.
00:11
This is diagram.
00:19
Here is vagon.
00:33
This is 20mg divided 20.
00:39
Here, m .a.
00:46
Now, this is, this is like this.
01:07
Here, p1 and mg, 1 ratio 20.
01:24
So they are 4 torque generate number 1, talks on drum shaft to accelerate load.
01:31
Number 2, torque on drum to accelerate drum shaft.
01:35
Number 3, talk on armature to accelerate drum and load.
01:39
Number 4, torque on armature to accelerate armature shaft.
01:44
So now tension in rope, tension in rope is equal to total forces p .1.
02:03
So p1 is equal to component of weight of weight plus inertial force, inertiaia force, plus frictional resistance, that is horizontal forces, equal to mg plus 1 divided by 20 plus m .a.
02:54
Here, mg multiply 1 divided by 20 plus m .a plus f.
03:08
P equal to 14 ,000 multiply 9 .81 divided by 20 plus 14 ,000 multiplied 0 .1 plus 14 ,000 multiplied 0 .1 plus 1 ,200.
03:38
So, p equal to 9467 newton.
03:50
So the torque on the drum to accelerate load is given by t1 equal to p1...