0821 L·atm/(mol·K))
- T is the temperature of the gas in Kelvin
Given:
- n = 6 moles
- V = 5 L
- T = 300 K
Now, let's substitute the given values into the ideal gas law equation:
\( P \cdot 5 \mathrm{~L} = 6 \mathrm{~mol} \cdot 0.0821 \mathrm{~L \cdot atm/(mol
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