4. Determine the magnitude of the moment due to the force F along the CB axis. (50 pts) y C (0, 4, 0) m F = -2i + 6j + 3k (kN) A (4, 2, 2) m B (0, 0, 3) m x z
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The position vector is given by the difference between the coordinates of the two points: CB = B - C = (0, 0, 3) - (4, 2, 2) = (-4, -2, 1) m Show more…
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