00:01
Hi, i'm david and i'm here to have janssen your question.
00:03
In the question here we are going to discuss about the possum distribution.
00:08
Let me remind to you that if we have the x that follows by the possum, when the mean equal to the lambda, and then probably to the x equal to the k, equal to e to the barma's lambda, lambda bauk, over k factorial.
00:26
Here we have the two questions, so let me do the question one first.
00:29
Well, we have the x that will follow by the portion with the lambda here equal equal to the 4.
00:37
And in the question a, i need to find the probability that the 6, it means then x to the 6.
00:46
Now it will apply this formula with the lambda equal to the 4.
00:49
We have e to the bar minus 4, 4 power 6 divided 6 factorial.
00:55
Now let me compute this one.
00:56
We have this will be the 4 this will be the 6 then we get equal to the 0 .1 .42 and i need to round the answer to the 4 decimal places and that's going to be the answer for the a.
01:17
For the b you want to find the probability of the x smaller than 6.
01:22
It means that would be the summation k -gur from 0 up to the 5 only, e to the power minus 4, 4 power k over k factorial.
01:32
And if we compute this one, we will have, then we get equal to the 0 .7, 8, 5, 1.
01:48
And for the question c, i need to find the probability of the x will be greater equal to the 6.
01:55
This will be the common element of the b, so equal to the 1 minus probability the x smaller than the 6.
02:03
Don't forget equal to 1 minus 0 .7 .8 51.
02:07
So we have the 1 minus 0 .7 ,8, 51, equal to the 0 .149.
02:15
For the questions, d, want to find the probability that the x will be between the 4 and the 6, including.
02:27
So this is an equal to the summation k -gler from the 4 to the 6, and then e to the bar minus 4, 4 over k over k, and then we get this one will be equal to 618933 minus this will be the 4 0 .4 -347.
02:56
And equal to the zubon 4 -546.
03:01
And then that's bichmark the answer for the number 1...