Question

4) If 14.0 grams of C$_2$H$_4$ and 15.5 grams of O$_2$ are reacted in the balanced equation below 5.8 grams of CO$_2$ is collected, what is the excess reactant? C$_2$H$_4$ + 3 O$_2$ $\rightarrow$ 2 CO$_2$ + 2 H$_2$O (a) C$_2$H$_4$ (b) O$_2$ (c) CO$_2$ (d) H$_2$O (e) no correct answer given

          4)
If 14.0 grams of C$_2$H$_4$ and 15.5 grams of O$_2$ are reacted in the balanced equation below
5.8 grams of CO$_2$ is collected, what is the excess reactant?
C$_2$H$_4$ + 3 O$_2$ \(\rightarrow\) 2 CO$_2$ + 2 H$_2$O
(a) C$_2$H$_4$
(b) O$_2$
(c) CO$_2$
(d) H$_2$O
(e) no correct answer given

4)
If 14.0 grams of C2H4 and 15.5 grams of O2 are reacted in the balanced equation below
5.8 grams of CO2 is collected, what is the excess reactant?
C2H4 + 3 O2 → 2 CO2 + 2 H2O
(a) C2H4
(b) O2
(c) CO2
(d) H2O
(e) no correct answer given

Added by Zachary F.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Ronald Prasad

06/20/2022

Step 1

For the first question: Molar mass of C2H4 = 2(12.01 g/mol) + 4(1.01 g/mol) = 28.05 g/mol Molar mass of O2 = 2(16.00 g/mol) = 32.00 g/mol Molar mass of CO2 = 12.01 g/mol + 2(16.00 g/mol) = 44.01 g/mol Moles of C2H4 = 14.0 g / 28.05 g/mol = 0.498 mol Moles of O2 Show more…

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4) If 14.0 grams of C2H4 and 15.5 grams of O2 are reacted in the balanced equation below, 5.8 grams of CO2 is collected. What is the excess reactant? C2H4 + 3O2 -> 2CO2 + 2H2O (a) C2H4 (b) O2 (c) CO2 (d) H2O (e) No correct answer given 4) If 14.0 grams of C2H4 and 15.5 grams of O2 are reacted in the balanced equation below, 5.8 grams of CO is collected. What is the excess reactant? CH4 + 3O2 -> 2CO + 2H2O (a) CH4 (b) O2 (c) CO (d) H2O (e) No correct answer given