00:01
In the first question of this problem we are given that cardinality of a is equal to n.
00:07
We are asked to determine the cardinality of the set set, set of all x element of power set of a, such that cardinality of x is equal to 1.
00:18
That is, we need to find the elements in the power set of a, which is the set of all subsets of a, such that cardinality of the set, set is 1, that is it contains only one element.
00:42
Now, if x is of the form some set a where a is an element of the set a, then cardinality of this set x is set to be 1.
00:56
So since there are n elements in the set a, since its cardinality is n, there will be precisely an subsets.
01:07
Of a with one element and therefore the cardinality of the given set x element such that cardinality of x is equal to one the cardinality of this set is n itself since there are precisely n number of one element subsets for a set a with cardinalty n.
01:41
In the next question, we are given four sets.
01:45
The first set is power set of b minus power set of a...