Question

Let ??² f(x) dx = 4, ??³ f(x) dx = 15, ??² g(x) dx = -15, ??³ g(x) dx = -9, Use these values to evaluate the given definite integrals. a) ??² (f(x) + g(x)) dx = b) ??³ (f(x) - g(x)) dx = c) ??³ (3f(x) + 2g(x)) dx = d) Find the value a such that ??³ (af(x) + g(x)) dx = 0. a =

          Let
??² f(x) dx = 4, ??³ f(x) dx = 15, ??² g(x) dx = -15, ??³ g(x) dx = -9,
Use these values to evaluate the given definite integrals.
a) ??² (f(x) + g(x)) dx =
b) ??³ (f(x) - g(x)) dx =
c) ??³ (3f(x) + 2g(x)) dx =
d) Find the value a such that ??³ (af(x) + g(x)) dx = 0.
a =

Let
??² f(x) dx = 4, ??³ f(x) dx = 15, ??² g(x) dx = -15, ??³ g(x) dx = -9,
Use these values to evaluate the given definite integrals.
a) ??² (f(x) + g(x)) dx =
b) ??³ (f(x) - g(x)) dx =
c) ??³ (3f(x) + 2g(x)) dx =
d) Find the value a such that ??³ (af(x) + g(x)) dx = 0.
a =

Added by Erin S.

Calculus: Early Transcendentals

James Stewart 8th Edition

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05/23/2023

Step 1

We know that $\int f(x) dx = 15$ and $\int g(x) dx = -15$. So, we have: $\int (f(x) + g(x)) dx = \int f(x) dx + \int g(x) dx = 15 + (-15) = 0$ Show more…

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Let ∫₀² f(x) dx = 4, ∫₀³ f(x) dx = 15, ∫₀² g(x) dx = -15, ∫₂³ g(x) dx = -9. Use these values to evaluate the given definite integrals. a) ∫₀² (f(x) + g(x)) dx = b) ∫₀³ (f(x) - g(x)) dx = c) ∫₂³ (3f(x) + 2g(x)) dx = d) Find the value a such that ∫₀³ (af(x) + g(x)) dx = 0. a =

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Let ??² f(x) dx = 4, ??³ f(x) dx = 15, ??² g(x) dx = -15, ??³ g(x) dx = -9, Use these values to evaluate the given definite integrals. a) ??² (f(x) + g(x)) dx = b) ??³ (f(x) - g(x)) dx = c) ??³ (3f(x) + 2g(x)) dx = d) Find the value a such that ??³ (af(x) + g(x)) dx = 0. a =

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