00:01
Hello students, in this question, the ksp of ag2so4 is given as 1 .5 x 10 -5.
00:14
The reaction for dissociation of ag2so4 is 2ag plus plus so4 2-.
00:22
So, the solubility will be s2ss.
00:27
So, from this ksp is equals to ag plus whole square so4 2 - that is equals to 2s whole square into s.
00:39
That is equals to 1 .5 x 10 -5 is equals to 4s cube.
00:45
So, s is equals to 1 .5 x 10 -5 by 4 cube root.
00:51
That is equals to 0 .0155 mol per liter.
01:05
So, this is my solubility of ag2so4 in pure water.
01:13
Now, if we are adding suppose k2so4 of 0 .10 molar.
01:20
So, it is made up of strong acid and strong base.
01:25
So, it will broke up like this 2k plus plus so4 2-.
01:30
So, it will release 0 .10so4 2-.
01:33
So, we have to find the new solubility of ag2so4...