4. Suppose there are 8 men and 8 women. How many ways can we choose a committee that has 2 men and 2 women?
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This is a combination problem, which can be calculated using the formula for combinations: \[ \binom{n}{r} = \frac{n!}{r!(n-r)!} \] For choosing 2 men from 8: \[ \binom{8}{2} = \frac{8!}{2!(8-2)!} = \frac{8 \times 7}{2 \times 1} = 28 \] Show more…
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