Question

4. Two points A and B lie in a region of space where the x-component of the electric field is $E_x = 600$ (N/C). Two points A and B are on the x-axis where the x-coordinate of the point A is $x_A = 1.00$ cm, and the x-coordinate of the point B is at $x_B = 3.00$ cm. What is the potential difference $\Delta V = V_B - V_A$ between these two points? A. 12.0 V B. - 12.0 V C. $3.00 \times 10^4$ V D. $-3.00 \times 10^4$ V

Name: 4 two points a and b lie in a region of space where the x component of the electric field is ex 600 nc two points a and b are on the x axis where the x coordinate of the point a is xa 100 48575
Uploaded: 2023-08-20T06:10:18-08:00
Duration: 1 min 21 s
Channel: Ankur S
Description: 4 two points a and b lie in a region of space where the x component of the electric field is ex 600 nc two points a and b are on the x axis where the x coordinate of the point a is xa 100 48575

          4. Two points A and B lie in a region of space where the x-component of the electric field is $E_x = 600$ (N/C). Two points A and B are on the x-axis where the x-coordinate of the point A is $x_A = 1.00$ cm, and the x-coordinate of the point B is at $x_B = 3.00$ cm. What is the potential difference $\Delta V = V_B - V_A$ between these two points?
A. 12.0 V
B. - 12.0 V
C. $3.00 \times 10^4$ V
D. $-3.00 \times 10^4$ V

4 two points a and b lie in a region of space where the x component of the electric field is ex 600 nc two points a and b are on the x axis where the x coordinate of the point a is xa 100 48575

Added by Nicole M.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Ankur S

08/20/2023

Step 1

Step 1: The potential difference between two points A and B in a uniform electric field is given by: $\Delta V = V_B - V_A = - \int_A^B \vec{E} \cdot d\vec{l}$ Since the electric field is in the x-direction, and the points A and B are on the x-axis, the dot product Show more…

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4. Two points A and B lie in a region of space where the x-component of the electric field is $E_x = 600$ (N/C). Two points A and B are on the x-axis where the x-coordinate of the point A is $x_A = 1.00$ cm, and the x-coordinate of the point B is at $x_B = 3.00$ cm. What is the potential difference $\Delta V = V_B - V_A$ between these two points? A. 12.0 V B. - 12.0 V C. $3.00 \times 10^4$ V D. $-3.00 \times 10^4$ V