We have two 3 Ω resistors in parallel, so their equivalent resistance is:
$R_{eq} = \frac{R_1 \cdot R_2}{R_1 + R_2} = \frac{3 \cdot 3}{3 + 3} = \frac{9}{6} = 1.5 \, \Omega$
Now, we have a 10 Ω resistor in series with the equivalent 1.5 Ω resistor, so the total
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