00:01
All right, so for this problem, we want to find our extra line segments, effectively by extending from the different line segments that we already have.
00:11
So to do that, we first need to find the slope of our first line segment.
00:16
You can see that our first line segment is connecting together the points one, or, pardon me, one moment here.
00:23
Our first line segment is connecting together the points 54 .5, 5 .5 .5.
00:34
And 64 .5, 10.
00:39
The slope of this first line segment is going to be the change in y, 10 minus 5, divided by the change in x, 64 .5 minus 54 .5.
00:52
So we can see that that would be 5 over 10, giving us a slope of 0 .5.
00:57
Then we want to find our intercept by solving for b1, such that, for instance, we meet up with this point of 54 .5 and 5.
01:09
So you'd have to have that 5 is equal to 0 .5 times 54 .5 plus b.
01:18
Or b is equal to 5 minus 0 .5 times 54 .5, which will result in b equals negative 22 .25.
01:30
So our first line segment, the line segment going to the left from 54.
01:37
4 .55 is going to be given by y1 equals 0 .5 x minus 22 .25.
01:45
Now we want to solve for x.
01:47
I'll call this x0 by finding the x values such that y equals 0 .5 x1 minus 22 .25.
02:01
Or pardon me, 0 equals 0 .5x1 minus 22 .25, which then means that 22 .25, must be equal to 0 .5x1, or pardon me, i should call that x -0, which then means that x -0 is 22 .25 over 0 .5, or x -0 is going to be equal to 44 .5...