42. The average pOH of normal arterial blood is 6.22. At normal body temperature (37 °C), $K_w = 2.4 \times 10^{-14}$. For blood at this temperature, calculate: A) $[H_3O^+]$ B) $[OH^-]$ C) pH
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Therefore, [OH-] = 10^-pOH = 10^-6.22 = 6.03 x 10^-7 M. Show more…
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The average pH of normal arterial blood is 7.40. At normal body temperature (37 °C), Kw = 2.4 x 10^-14. Calculate [H+], [OH-], and pOH for blood at this temperature.
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The average $\mathrm{pH}$ of normal arterial blood is $7.40 .$ At normal body temperature $\left(37^{\circ} \mathrm{C}\right), K_{w}=2.4 \times 10^{-14} \cdot$ Calculate $\left[\mathrm{H}^{+}\right]$ $\left[\mathrm{OH}^{-}\right],$ and $\mathrm{pOH}$ for blood at this temperature. $$ \begin{array}{llll} \hline \text { pH } & \text { pOH } & \text { [H }^{+} \text {] } & \text { [OH }^{-} \text {] } & \text { Acidic or basic? } \\ \hline 5.25 & & & \\ & 2.02 & & \\ & & 4.4 \times 10^{-10} M & & \\ & & & 8.5 \times 10^{-2} M & \\ \hline \end{array} $$
At 40°C, the pH of pure water is 6.77. a) What is [H3O+] in pure water at 40°C? b) What is the pOH of pure water at 40°C? c) Calculate Kw at 40°C.
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