420pts5 each a bullet with mass mm and velocity via v is fired horizontally toward a wooden bloc

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A bullet with mass m and velocity ViA = v is fired horizontally toward a wooden block with mass m = 5m that is hanging from strings as a ballistic pendulum. The bullet reverses its direction and has speed V2a = v/2 after the collision as shown in the adjacent Figure. a) Find the speed Vs of the block just after the collision. Is the collision between the bullet and the block elastic or inelastic? (You must show your work to receive any credit). Explain. Using energy considerations, find the maximum height h to which the block rises after the collision. If this collision lasted t units of time, find the magnitude and direction of the average force exerted by the wooden block on the bullet. Express your answers in terms of any or all of the variables v, m, t, and g (acceleration due to gravity). hmax = V^2 / (2g) (a) F = M (Bullet-System) + M (Block-System) k++ = +ug operating mass = m EFe = hu = mghmax mB = 5m J = F VAL = 29 MAV J = F6 SP AW mv + 5m = 06 DE 2 P2 - P 2mv mv = mv DE mv - mv 2 2 2 Sw = 10 5m Ym = mv 5m oF Block Systemalter Collisio -mv 10 Fava 2 (n) 100 -mv Favg = 26 Svv2 6v2 = 4 20 C 20 20 m = m + 5m KE was lost by a fudof 27 of/2onelashc (mv)^2 / 5 = 100 Page 6/7

          A bullet with mass m and velocity ViA = v is fired horizontally toward a wooden block with mass m = 5m that is hanging from strings as a ballistic pendulum. The bullet reverses its direction and has speed V2a = v/2 after the collision as shown in the adjacent Figure. 
a) Find the speed Vs of the block just after the collision. Is the collision between the bullet and the block elastic or inelastic? (You must show your work to receive any credit). Explain. 
Using energy considerations, find the maximum height h to which the block rises after the collision. 
If this collision lasted t units of time, find the magnitude and direction of the average force exerted by the wooden block on the bullet. 
Express your answers in terms of any or all of the variables v, m, t, and g (acceleration due to gravity). 

hmax = V^2 / (2g)
(a) F = M (Bullet-System) + M (Block-System)
k++ = +ug
operating mass = m
EFe = hu = mghmax
mB = 5m
J = F
VAL = 29 MAV
J = F6 SP AW
mv + 5m = 06 DE 2 P2 - P 2mv
mv = mv
DE mv - mv
2 2 2
Sw = 10 5m
Ym = mv 5m
oF Block Systemalter Collisio -mv
10 Fava 2 (n) 100 -mv
Favg = 26 Svv2
6v2 = 4 20 C 20 20
m = m + 5m
KE was lost by a fudof 27 of/2onelashc
(mv)^2 / 5 = 100

Page 6/7

420pts5 each a bullet with mass mm and velocity via v is fired horizontally toward a wooden block with mass m 5m that is hanging from strings as a ballistic pendulum the bullet reverses its 07552

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