00:01
Hi there.
00:02
A firm determines that x units of its product can be sold daily at p dollars per unit, where x is equal to 1000 minus p.
00:13
The cost of producing x units per day is given by the function c of x, which is equal to 3 ,000 plus 20x.
00:22
We wish to find the revenue function, that is, r of x, which is r of x, which is, r of x, which is, which will be equal to the number of units sold multiplied by cost of each unit.
00:50
So this will be equal to x multiplied by p.
00:58
And since p is equal to 1 ,000 minus x, you get this to be equal to x multiplied by 1 ,000 minus x.
01:12
So that is 1000x minus x square.
01:19
Therefore, the revenue function r of x is equal to 1000x minus x square.
01:27
Next, we want to find the profit function, that is p of x, which will be equal to the revenue minus the cost.
01:44
So this will be equal to 1000 x minus x squared minus 3 ,000 plus 20x.
02:02
That is equal to 980x minus x squared minus 3 ,000.
02:11
Therefore, the profit function p of x is equal to 980x minus 8 .6 minus 8.
02:18
X squared minus 3 ,000.
02:22
Now we are given that production capacity that is x per day is at most 500 units.
02:34
That is x is less than equal to 500...