00:01
Hello students, in this question given as a circuit and in the first part of the question this is asking about to redraw the circuit.
00:08
So, to redraw the circuit we will write the phasor in the appropriate form.
00:13
So, in this question given as the impedance is equals to 100 millihenry, capacitance value is 220 milli farad and resistance is 2 ohm and according to the given current form so omega is 10 ohm is given sorry ohm 10 radian per second is given.
00:44
So, for the impedance we will write the impedance for the inductance.
00:51
So, this will be equal to the j x l or j omega l.
00:57
Now this is equals to j omega is 10 into l is 100 10 to the power minus 3 henry.
01:06
So, this will be equal to the only j that is 1 ohm and similarly for the capacitor this is equals to the minus j upon sorry this value is minus j x c or minus j upon omega c.
01:30
So, minus j upon 10 into 220 10 to the power minus 3 farad.
01:37
So, after calculation this is equals to minus j and 0 .4545 the circuit will be this and will write the value there is the maximum current is 1 .5 and the angle which is given in the question minus 42 degree milli ampere and this value is 2 .5 and angle is 0 degree milli ampere and capacitance resistance this is the impedance due to the capacitor we have calculated minus j 0 .4545 ohm and the resistance is 2 ohm and the impedance due to the inductor is this is j 1 ohm.
02:35
In the next part of the question we have to calculate the current in all three loops...