0:00
High.
00:01
Now given the polar curve as r is equal to cos square theta by 2 theta lying from 0 to 2 pi.
00:12
Now in part a we have to find the arc length of the curve.
00:16
So arc length is given by the formula integral alpha to beta.
00:20
Alpha and beta are the range for theta.
00:24
Under the root r square plus dr by d theta whole square into d theta.
00:30
So for this we first find dr by d theta.
00:33
So dr by d theta will be equal to 2 cos theta by 2 into cos theta by 2 is minus sin theta by 2 into 1 by 2 for this derivative of theta by 2.
00:46
So this is simply equal to minus cos theta by 2 and sin theta by 2.
00:51
So we put it over here so we have 0 to 2 pi under the root r square becomes cos to the power 4 theta by 2 and this becomes cos square theta by 2 sin square theta by 2 d theta.
01:06
So this is further equal to 0 to 2 pi under the root cos square theta by 2 cos square theta by 2 plus sin square theta by 2 d theta.
01:20
So now this becomes 1 so this is equal to integral 0 to 2 pi mod cos theta by 2 d theta which can be written as 2 times integral 0 to pi cos theta by 2 d theta.
01:34
So this is simply equal to 2 sin theta by 2...