4. Determine the phase angle by which $v_1(t)$ leads $i_1(t)$ and $v_1(t)$ leads $i_2(t)$, where $v_1(t) = 4cos(377t + 25^\circ) V$ $i_1(t) = 0.05cos(377t - 20^\circ) A$ $i_2(t) = -0.1cos(377t + 45^\circ) A$ 5. Find Z in the network in Figure 2.
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To find the phase angle, we need to compare the phase angles of the two signals. The phase angle of a cosine function can be found by looking at the coefficient of t in the argument of the cosine function. For v(t) = 4cos(377t + 25°) V, the phase angle is Show more…
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2- Three branch currents in a network are known to be i(t) = 2 sin(377t + 459) A, ix(t) = 0.5 cos(377t + 109) A, i3(t) = -0.25 sin(377t + 609) A. Determine the phase angles by which a) i(t) leads iz(t) b) i(t) leads is(t) [Answer: a) i1 leads i2 by 550 b) i leads is by 1659]
Jagjit Singh C.
Determine the phase angles by which $v_{1}(t)$ leads $i_{1}(t)$ and $v_{1}(t)$ leads $i_{2}(t),$ where $$\begin{array}{l}v_{1}(t)=4 \sin \left(377 t+25^{\circ}\right) \mathrm{V} \\i_{1}(t)=0.05 \cos \left(377 t-20^{\circ}\right) \mathrm{A} \\i_{2}(t)=-0.1 \sin \left(377 t+45^{\circ}\right) \mathrm{A}\end{array}$$
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