Question

Consider the indefinite integral $\int \frac{4x^3 + 9x^2 + 8x + 24}{x^4 + 4x^2} dx$. The integrand has partial fractions decomposition $\frac{a}{x^2} + \frac{b}{x} + \frac{cx + d}{x^2 + 4}$ where a = b = c = d = Integrating term by term, and using K for the constant of integration, we obtain that $\int \frac{4x^3 + 9x^2 + 8x + 24}{x^4 + 4x^2} dx = $

          Consider the indefinite integral \(\int \frac{4x^3 + 9x^2 + 8x + 24}{x^4 + 4x^2} dx\).
The integrand has partial fractions decomposition
\(\frac{a}{x^2} + \frac{b}{x} + \frac{cx + d}{x^2 + 4}\)
where
a = 

b = 

c = 

d = 
Integrating term by term, and using K for the constant of integration, we obtain that
\(\int \frac{4x^3 + 9x^2 + 8x + 24}{x^4 + 4x^2} dx = \)

$Consider the indefinite integral ∫(4x^3 + 9x^2 + 8x + 24)/(x^4 + 4x^2) dx. The integrand has partial fractions decomposition (a)/(x^2) + (b)/(x) + (cx + d)/(x^2 + 4) where a = b = c = d = Integrating term by term, and using K for the constant of integration, we obtain that ∫(4x^3 + 9x^2 + 8x + 24)/(x^4 + 4x^2) dx =$

Added by Kathy H.

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