Question

5. A step response test is performed on a 2nd order system and the result shows that the time to the first peak is 0.847 s, the percentage overshoot is 28.1% and the final value of the output is half the input step magnitude. What is the transfer function? 6. Consider the system that has both the position and velocity feedback in Fig.TS3-3. Find the value of $\beta$ that yields a percentage overshoot that is only one-fifth as large as the percentage overshoot obtained for $\beta$=0. Fig.TS3-3 $U(s)$ \\ $+$ \\ $\frac{200}{s(s+2)}$ $Y(s)$ \\ $\beta s$

          5.
A step response test is performed on a 2nd order system and the result shows that the
time to the first peak is 0.847 s, the percentage overshoot is 28.1% and the final value of
the output is half the input step magnitude. What is the transfer function?
6. Consider the system that has both the position and
velocity feedback in Fig.TS3-3. Find the value of $\beta$
that yields a percentage overshoot that is only one-fifth
as large as the percentage overshoot obtained for $\beta$=0.
Fig.TS3-3
$U(s)$ \\
$+$ \\
$\frac{200}{s(s+2)}$
$Y(s)$ \\
$\beta s$

5.
A step response test is performed on a 2nd order system and the result shows that the
time to the first peak is 0.847 s, the percentage overshoot is 28.1% and the final value of
the output is half the input step magnitude. What is the transfer function?
6. Consider the system that has both the position and
velocity feedback in Fig.TS3-3. Find the value of β
that yields a percentage overshoot that is only one-fifth
as large as the percentage overshoot obtained for β=0.
Fig.TS3-3
U(s)

+

(200)/(s(s+2))
Y(s)

β s

Added by Catalina M.

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