5. An electron, after being accelerated through a potential difference of 100.0 V, enters a uniform magnetic field of 0.0400 T perpendicular to its direction of motion. Calculate the radius of the path described by the electron.
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We can use the equation: V = β(2qV/m) where V is the velocity, q is the charge of the electron (1.6 x 10^-19 C), V is the potential difference (100.0 V), and m is the mass of the electron (9.11 x 10^-31 kg). Plugging in the values, we get: V = β(2 * 1.6 x Show moreβ¦
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