00:01
Hello, in this question you are given that there is a sled on which your sister is lying.
00:09
So they combined heavy rate of 350 newton.
00:13
So this will be acting vertically downwards.
00:17
So ground will be giving a normal course that will be acting upwards and you are pulling it with a force f at an angle 30 degree with the horizontal.
00:26
All right.
00:27
There is a friction force acting that will oppose the motion.
00:30
So if it is moving in the forward direction, the friction force will be acting in the backward direction.
00:36
That will be presented by the small.
00:38
Okay.
00:39
So the maximum value of friction is new kinetic into n because the body is already in the motion.
00:55
So if the motion between two body has started then the coefficient of friction acting between them would be kinetic friction.
01:03
All right so if they are moving then the value of friction would be like this so it would be equal to so if i take component of the force f it would be f course 30 and it would be f sine all right so if i balance the forces in the vertical direction it would be n plus f sine 30 that must be equal to 350 and if i balance the forces because it is moving with a constant velocity so acceleration in the whole horizontal direction is also 0 that means net force in the horizontal direction is also 0 that means fose 30 is equal to mu kinetic into n so n was equal to from this first equation we can calculate to n all right so putting the value of n from the first equation in the second equation f root 3 by 2 is equal to 0 .15 into 350 minus f into 1 by 2.
02:08
So the value of f can be calculated.
02:10
Let me solve it 2 .1 1 % into 350 minus x.
02:29
So the value of f is coming out to be 55 .79 no touch.
02:36
So this much force is required to pull...