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5. [0/14.28 Points] DETAILS PREVIOUS ANSWERS Find the general solution of the given system. $x' = \begin{pmatrix} -1 & 7 \ -7 & 13 \end{pmatrix} x$ $x(t) = C_1 \begin{pmatrix} 1 \ 1 \end{pmatrix} e^{3t} + C_2 \begin{pmatrix} 1 \ 1 \end{pmatrix} te^{3t} + \begin{pmatrix} -\frac{1}{5} \ 0 \end{pmatrix} e^{3t}$

          5. [0/14.28 Points]
DETAILS
PREVIOUS ANSWERS
Find the general solution of the given system.
$x' = \begin{pmatrix} -1 & 7 \ -7 & 13 \end{pmatrix} x$
$x(t) = C_1 \begin{pmatrix} 1 \ 1 \end{pmatrix} e^{3t} + C_2 \begin{pmatrix} 1 \ 1 \end{pmatrix} te^{3t} + \begin{pmatrix} -\frac{1}{5} \ 0 \end{pmatrix} e^{3t}$
        
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5. [0/14.28 Points]
DETAILS
PREVIOUS ANSWERS
Find the general solution of the given system.
x' = 
    < p m a t r i x >
 x
x(t) = C1 
    < p m a t r i x >
 e^3t + C2 
    < p m a t r i x >
 te^3t + 
    < p m a t r i x >
 e^3t

Added by Brianna C.

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Calculus: Early Transcendentals
Calculus: Early Transcendentals
James Stewart 8th Edition
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Find the general solution of the given system. x - x' = c1e^(3t)
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Transcript

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00:05 Given differential equation double dash t minus 6y dash of t plus 9y of t is equals to e to the power 3 t.
00:27 Now we can write it like that.
00:32 D2y of t upon dt square minus 6 dy of t upon dt plus 9y of t is equals to e to the power 3t.
00:59 Now first we will find complementary solution.
01:04 Yc is equals to d2y of t upon dt square minus 6 dy by dt of t plus 9y of t is equals to 0.
01:23 Now put y of t is equals to e to the power lambda t.
01:30 Now an equation will be d2y of t sorry y of lambda e to the power lambda t upon dt square minus 6 dy by dt of e to the power lambda t plus 9 into e to the power lambda t is equals to 0.
02:02 Now by differentiating with respect to t we will get lambda square e to the power lambda t minus 6 lambda e to the power lambda t plus 9 into e to the power lambda t is equals to 0.
02:23 Now by solving it we get lambda is equals to 3 and lambda is equals to 3...
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