5.1 Let \( f(x)=2 x^{3}-3 x^{2}-72 x+15 \). (a) Find the relative extrema values of \( f(x) \) using the first derivative test. (b) Determine the open interval on which the function \( f(x) \) is increasing and decreasing. (c) Find \( f^{\prime \prime}(x) \).
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Given \( f(x) = 2x^3 - 3x^2 - 72x + 15 \), the first derivative \( f'(x) \) is found by differentiating \( f(x) \) with respect to \( x \). This gives: \[ f'(x) = \frac{d}{dx}(2x^3) - \frac{d}{dx}(3x^2) - \frac{d}{dx}(72x) + \frac{d}{dx}(15) \] \[ f'(x) = 6x^2 - Show more…
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