520 grams of water had an initial temperature of 21.0°C. It was then heated with 150 KJ of heat. If the specific heat capacity of water is 4.184 J/g°C then what is the final temperature of the water?
Added by Matthew T.
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Q = 520 g * 4.184 J/g°C * ΔT Q = 2178.88 ΔT J Show more…
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