59.0 mL of a 1.40 M solution is diluted to a total volume of 278 mL. A 139 mL portion of that solution is diluted by adding 129 mL of water. What is the final concentration? Assume the volumes are additive.
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Step 1
We can use the formula: C1V1 = C2V2 where C1 and V1 are the initial concentration and volume, and C2 and V2 are the final concentration and volume. (1.40 M)(59.0 mL) = C2(278 mL) C2 = (1.40 M)(59.0 mL) / (278 mL) C2 = 0.297 M Show more…
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