00:01
In this question given that cos -5 is equal to 0 .3031 -4 -5, 3 pi by 2 to 2 pi, and sine theta is negative 0 .3381 4 theta, pi to 3 pi by 2.
00:17
And here, by using these data, we will find the value of sine 5, 10 -5, cos theta and 10 theta.
00:25
So let's start to solve this problem.
00:27
Here this is coordinate system, this is first quadrant, this is second quadrant, this is third quadrant and this is fourth quadrant.
00:39
Here, phi belongs to fourth quadrant, so here five.
00:44
And theta belongs to third quadrant.
00:49
So here theta.
00:52
And we know in a fourth quadrant only course and secar position.
00:59
And in a third quadrant only 10 and code are positive.
01:06
Now first we find the value of sine 5 and 10 5.
01:09
So here the value of cos 5 is equal to 0 .303 and 1 and we know cos 5 is the ratio of base over hypotenous.
01:21
Here base is equal to 0 .3031 and let us assume that the hypotenous is equal to 1.
01:29
So base over hypotenus will come equal to 0 .3031.
01:34
Now by using pythagoras theorem we can find perpendicular and perpendicular is equal to square root of hypotenous square minus base square.
01:45
So perpendicular will come equal to 1 minus 0 .3031 whole square and this will come equals to 0 .9529.
01:59
Now we know sine phi is the ratio of perpendicular and hypotenous.
02:09
And here this ratio is negative because phi lies in the fourth quadrant.
02:16
Now we put the value of here p and h.
02:20
So by putting the value of p and h, we obtain the value of p and h, we obtain the value of sine 5 is equal to negative 0 .95 to 9...