Question

\begin{equation} \begin{cases} -5x + 4y + z = 17 \\ -4x + 5y = 21 \\ 3x + y + 5z = 18 \end{cases} \end{equation} A) Apply elimination process and write the Upper Triangular system below: \begin{equation} \begin{cases} x + y + z = \\ x + y + z = \\ x + y + z = \end{cases} \end{equation} You're finished if one of the following happens after elimination step (2): 1) the first 2 coefficients in equation 2 are all zeros immediately after elimination step (2). Simply swap your equation 2 and 3 to obtain your final Upper Triangular system. 2) the first 2 coefficients in equation 3 are all zeros immediately after elimination step (2). Your system is already in its Upper Triangular form. B) From the completed Upper Triangular system, solve the system by back substitution. \begin{equation} \begin{bmatrix} x \\ y \\ z \end{bmatrix} = \begin{bmatrix} \\ \\ \end{bmatrix} \end{equation}

          \begin{equation*} \begin{cases} -5x + 4y + z = 17 \\ -4x + 5y = 21 \\ 3x + y + 5z = 18 \end{cases} \end{equation*} A) Apply elimination process and write the Upper Triangular system below: \begin{equation*} \begin{cases} x + y + z = \\ x + y + z = \\ x + y + z = \end{cases} \end{equation*} You're finished if one of the following happens after elimination step (2): 1) the first 2 coefficients in equation 2 are all zeros immediately after elimination step (2). Simply swap your equation 2 and 3 to obtain your final Upper Triangular system. 2) the first 2 coefficients in equation 3 are all zeros immediately after elimination step (2). Your system is already in its Upper Triangular form. B) From the completed Upper Triangular system, solve the system by back substitution. \begin{equation*} \begin{bmatrix} x \\ y \\ z \end{bmatrix} = \begin{bmatrix} \\ \\ \end{bmatrix} \end{equation*}

-5x + 4y + z = 17
-4x + 5y = 21
3x + y + 5z = 18
A) Apply elimination process and write the Upper Triangular system below:
x + y + z =
x + y + z =
x + y + z =
You're finished if one of the following happens after elimination step (2): 1) the first 2 coefficients in equation 2 are all zeros immediately after elimination step (2). Simply swap your equation 2 and 3 to obtain your final Upper Triangular system. 2) the first 2 coefficients in equation 3 are all zeros immediately after elimination step (2). Your system is already in its Upper Triangular form. B) From the completed Upper Triangular system, solve the system by back substitution.
< b m a t r i x >
=
< b m a t r i x >

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