Question

6. [- / 1 Points] Determine whether the sequence converges or diverges. If it converges, find the limit. (If an answer does not exist, enter DNE.) $$a_n = \frac{n^4}{n^3 - 2n}$$ $$\lim_{n \to \infty} a_n =$$ Need Help? Read It SUBMIT ANSWER

Name: 6 1 points determine whether the sequence converges or diverges if it converges find the limit if an answer does not exist enter dne an fracn4n3 2n limn to infty an need help read it subm 41806
Uploaded: 2018-01-31T02:10:10-08:00
Duration: 1 min 20 s
Channel: Gabriel Rhodes
Description: 6 1 points determine whether the sequence converges or diverges if it converges find the limit if an answer does not exist enter dne an fracn4n3 2n limn to infty an need help read it subm 41806

          6. [- / 1 Points]
Determine whether the sequence converges or diverges. If it converges, find the limit. (If an answer does not exist, enter DNE.)
$$a_n = \frac{n^4}{n^3 - 2n}$$
$$\lim_{n \to \infty} a_n =$$
Need Help?
Read It
SUBMIT ANSWER

$6 1 points determine whether the sequence converges or diverges if it converges find the limit if an answer does not exist enter dne an fracn4n3 2n limn to infty an need help read it subm 41806$

Added by Roger G.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Gabriel Rhodes

01/31/2018

Step 1

The given sequence is $a_n = \frac{n^4}{n^3 - 2n}$. Step 2: To evaluate the limit $\lim_{n \to \infty} \frac{n^4}{n^3 - 2n}$, we can divide both the numerator and the denominator by the highest power of $n$ in the denominator, which is $n^3$. $$ \lim_{n \to Show more…

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6. [- / 1 Points] Determine whether the sequence converges or diverges. If it converges, find the limit. (If an answer does not exist, enter DNE.) $$a_n = \frac{n^4}{n^3 - 2n}$$ $$\lim_{n \to \infty} a_n =$$ Need Help? Read It SUBMIT ANSWER