4$ µF
The 6 µF and 2.4 µF capacitors are in parallel, their equivalent capacitance is:
$C_{eq3} = 6 + 2.4 = 8.4$ µF
The 12 µF and 8.4 µF capacitors are in series, their equivalent capacitance is:
$C_T = \frac{12 \times 8.4}{12 + 8.4} = \frac{100.8}{20.4} \approx
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