If D is the distance between the skew lines L=ty=tz and LT=1y=2, then D^2 = A6B1C2D4. 1 (A (c) A
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For the line L: ty = tz, we can rewrite it as y = z/t. This means that the direction vector of L is (0, 1/t, 1). For the line LT: 1y = 2, we can rewrite it as y = 2. This means that the direction vector of LT is (0, 1, 0). Show more…
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