[6 points] Find the volume of the solid obtained when the region bounded by \(y = x^2\) and \(y = x^4\) in the first quadrant \((x > 0)\), is revolved about the y-axis.
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$x^2 = x^4$ $x^4 - x^2 = 0$ $x^2(x^2 - 1) = 0$ $x^2 = 0$ or $x^2 - 1 = 0$ $x = 0$ or $x = 1$ or $x = -1$ Since we are in the first quadrant, we only consider $x = 0$ and $x = 1$. Show more…
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