6. Solve the differential equation: y\" + 2y\' + 2y = \cos t + \delta(t - \pi/2) y(0) = 0, y'(0) = 0
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The homogeneous solution is found by setting the right-hand side of the equation to zero. So, we have the equation y'' + 2y' + 2y = 0. The characteristic equation is r^2 + 2r + 2 = 0. Using the quadratic formula, we find that the roots are r = -1 + i and r = -1 - Show more…
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