Question

Use substitution to find the indefinite integral $\int \frac{6}{(3x - 7)^3} dx$. $\int \frac{6}{(3x - 7)^3} dx = \Box$

          Use substitution to find the indefinite integral $\int \frac{6}{(3x - 7)^3} dx$.
$\int \frac{6}{(3x - 7)^3} dx = \Box$
        
Use substitution to find the indefinite integral ∫(6)/((3x - 7)^3) dx.
∫(6)/((3x - 7)^3) dx =

Added by Victor K.

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Calculus: Early Transcendentals
Calculus: Early Transcendentals
James Stewart 8th Edition
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6 Use substitution to find the indefinite integral (3-7 dx. 6 d= 3x-7
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Transcript

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00:01 In this question we have to integrate the function that is i can see that sign of 6x minus 7 okay to integrate this function with the help of substitution let i'm going to substitute u is equal to 6x minus 7 now we differentiate it so we get here d u is equal to 6 d x okay now we want 6 as a coefficient here so i'm going to multiply and divide by 6 here so after multiply and dividing by six see what happens in our integration that is 1 by 6 sign of 6x minus…
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